Why do rational functions have discontinuities




















A large mixing tank currently contains gallons of water into which 5 pounds of sugar have been mixed. A tap will open pouring 10 gallons per minute of water into the tank at the same time sugar is poured into the tank at a rate of 1 pound per minute. Find the concentration pounds per gallon of sugar in the tank after 12 minutes.

Is that a greater concentration than at the beginning? Let t be the number of minutes since the tap opened. Since the water increases at 10 gallons per minute, and the sugar increases at 1 pound per minute, these are constant rates of change.

This tells us the amount of water in the tank is changing linearly, as is the amount of sugar in the tank. We can write an equation independently for each:.

To find the horizontal asymptote, divide the leading coefficient in the numerator by the leading coefficient in the denominator:. There are 1, freshmen and 1, sophomores at a prep rally at noon.

After 12 p. Find the ratio of freshmen to sophomores at 1 p. A vertical asymptote represents a value at which a rational function is undefined, so that value is not in the domain of the function. A reciprocal function cannot have values in its domain that cause the denominator to equal zero.

In general, to find the domain of a rational function, we need to determine which inputs would cause division by zero. The domain of a rational function includes all real numbers except those that cause the denominator to equal zero. We will discuss these types of holes in greater detail later in this section.

By looking at the graph of a rational function, we can investigate its local behavior and easily see whether there are asymptotes. We may even be able to approximate their location. Even without the graph, however, we can still determine whether a given rational function has any asymptotes, and calculate their location. The vertical asymptotes of a rational function may be found by examining the factors of the denominator that are not common to the factors in the numerator.

Vertical asymptotes occur at the zeros of such factors. How To: Given a rational function, identify any vertical asymptotes of its graph. To find the vertical asymptotes, we determine where this function will be undefined by setting the denominator equal to zero:. Occasionally, a graph will contain a hole: a single point where the graph is not defined, indicated by an open circle.

We call such a hole a removable discontinuity. We factor the numerator and denominator and check for common factors. If we find any, we set the common factor equal to 0 and solve. This is the location of the removable discontinuity. This is true if the multiplicity of this factor is greater than or equal to that in the denominator. If the multiplicity of this factor is greater in the denominator, then there is still an asymptote at that value. While vertical asymptotes describe the behavior of a graph as the output gets very large or very small, horizontal asymptotes help describe the behavior of a graph as the input gets very large or very small.

Note that this graph crosses the horizontal asymptote. As the inputs grow large, the outputs will grow and not level off, so this graph has no horizontal asymptote. This line is a slant asymptote. Notice that, while the graph of a rational function will never cross a vertical asymptote , the graph may or may not cross a horizontal or slant asymptote.

Also, although the graph of a rational function may have many vertical asymptotes, the graph will have at most one horizontal or slant asymptote. It should be noted that, if the degree of the numerator is larger than the degree of the denominator by more than one, the end behavior of the graph will mimic the behavior of the reduced end behavior fraction. For instance, if we had the function. The horizontal asymptote of a rational function can be determined by looking at the degrees of the numerator and denominator.

Both the numerator and denominator are linear degree 1. Because the degrees are equal, there will be a horizontal asymptote at the ratio of the leading coefficients. In the denominator, the leading term is 10t, with coefficient The horizontal asymptote will be at the ratio of these values:. First, note that this function has no common factors, so there are no potential removable discontinuities. The function will have vertical asymptotes when the denominator is zero, causing the function to be undefined.

Since a fraction is only equal to zero when the numerator is zero, x-intercepts can only occur when the numerator of the rational function is equal to zero. Given the reciprocal squared function that is shifted right 3 units and down 4 units, write this as a rational function.

Then, find the x- and y-intercepts and the horizontal and vertical asymptotes. As with polynomials, factors of the numerator may have integer powers greater than one. We wouldn't want to cross an asymptote either; we've heard some scary rumors. It isn't quite always true, though. Sorry, but there is one big exception to this rule. It's what happens when division by zero cancels out of a rational expression. This is the graph of. We only have one vertical asymptote, though.

Is everything we thought a lie? The line just skips over -1, so the line isn't continuous at that point. It's not as dramatic a discontinuity as a vertical asymptote, though. In general, we find holes by falling into them. We don't pay a lot of attention to where we're walking.

In rational expressions, we find holes by simplifying the expression. Dahen Dahen 2 2 silver badges 11 11 bronze badges. Neither your examples are. Add a comment. Active Oldest Votes. That isnt continuous at that point, right? Alot of the examples on discontinuity points are also on rational functions. Show 2 more comments. Sign up or log in Sign up using Google. Sign up using Facebook. Sign up using Email and Password. Post as a guest Name. Email Required, but never shown.



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